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单链表快速排序
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public class LinkedListSortTest {
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//bubble up
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public static ListNode sortList(ListNode head) {
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ListNode m = head;
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ListNode tail = null;
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while (m != tail && m.next != null) {
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ListNode n = head;
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while (n.next != null) {
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if (n.next.val < n.val) {
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swap(n, n.next);
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}
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n = n.next;
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}
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tail = n;
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m = m.next;
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}
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return head;
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}
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//quick sort
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public static ListNode sortList2(ListNode head) {
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ListNode next = head.next;
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if (next == null) { // 1 element
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return head;
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} else if (next.next == null) { // 2 elements
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if (head.val > next.val) {
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swap(head, next);
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}
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return head;
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} else {
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ListNode mid = getMidNode(head);
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return merge(sortList(head), sortList(mid));
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}
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}
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private static ListNode merge(ListNode m, ListNode n) {
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// System.out.println("Merge " + m + " with " + n);
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ListNode head = new ListNode(0);
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ListNode tail = head;
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while (m != null && n != null) {
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if (m.val < n.val) {
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tail.next = m;
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m = m.next;
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} else {
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tail.next = n;
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n = n.next;
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}
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tail = tail.next;
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}
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if (m != null) {
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tail.next = m;
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}
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if (n != null) {
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tail.next = n;
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}
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// System.out.println("Merge result : " + head.next);
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return head.next;
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}
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private static ListNode getMidNode(ListNode n) {
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ListNode fast = n;
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ListNode slow = n;
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while (true){
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if (fast.next != null) {
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fast = fast.next;
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if (fast.next != null) {
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fast = fast.next;
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slow = slow.next;
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continue;
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}
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}
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break;
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}
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ListNode mid = slow.next;
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slow.next = null;
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return mid;
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}
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private static void swap(ListNode n, ListNode m) {
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int v = n.val;
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n.val = m.val;
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m.val = v;
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}
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public static void main(String[] args) {
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ListNode head = new ListNode(0);
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int i = 0;
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ListNode n = head;
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while (i++ < 20) {
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n.next = new ListNode(i * 37 % 50);
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// n.next = new ListNode(i);
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n = n.next;
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}
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print(head);
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print(sortList(head));
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print(sortList2(head));
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}
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public static void print(ListNode n) {
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while (n != null) {
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System.out.print(n.val + " ");
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n = n.next;
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}
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System.out.println();
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}
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}
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class ListNode {
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int val;
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ListNode next;
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ListNode(int x) {
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val = x;
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}
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public String toString() {
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ListNode n = this;
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StringBuilder sb = new StringBuilder("[");
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while (n != null) {
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sb.append(n.val + " ");
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n = n.next;
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}
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sb.deleteCharAt(sb.length() - 1);
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sb.append("]");
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return sb.toString();
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}
- }
148. Sort List
Sort a linked list in O(n log n) time using constant space complexity.
文章名称：单链表快速排序
转载注明：http://scpingwu.com/article/iiihdp.html
